Question

If ?h°rxn and ?s°rxn are both negative values, what drives the spontaneous reaction and in what direction at standard conditions?

Answer 1

Entropy Driven to The Left

Step-by-step explanation:

In the problem it mentions how both ΔH & ΔS are both negative that would lead to a entropy situation where the reaction is driven to the left.

Answer 2

The release of free energy drives the spontaneous reaction.

Spontaneity can be determined using the change in Gibbs free energy (the thermodynamic potencial):

delta G=delta H – T*delta S

where delta H is the enthalpy and delta S is the entropy.

The direction (the sign) of delta G depends of the changes of enthalpy and entropy. If delta G is negative then the process is spontaneous.

In our case, both delta H and delta S are negative values, the process as said is spontaneous which means that it may proceed in the forward direction.