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Assuming independent assortment, how many different gametes can be formed by an organism that is homozygous for three and heterozygous for two genes?

User CHP
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Assuming independent assortment, there are three homozygous genes and two heterozygous genes. The number of gamete that can be formed from these genes = 2^ [number of hetreozygous genes] = 2^2 = 4.
The number of gamete that can be formed is 4.
User Michael Moeller
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