Assuming independent assortment, how many different gametes can be formed by an organism that is homozygous for three and heterozygous for two genes?

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asked May 1, 2018 221k views

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Michael Moeller · Answer 1 · 2018-05-05T08:16:59+0000

Assuming independent assortment, there are three homozygous genes and two heterozygous genes. The number of gamete that can be formed from these genes = 2^ [number of hetreozygous genes] = 2^2 = 4.
The number of gamete that can be formed is 4.

Assuming independent assortment, how many different gametes can be formed by an organism that is homozygous for three and heterozygous for two genes?

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