Answer: The pOh of the given solution is 2.35
Step-by-step explanation:
pOH is defined as the negative logarithm of hydroxide ion concentration present in a solution. The equation used to represent pOH of the solution follows:
![pOH=-\log[OH^-]](https://img.qammunity.org/2018/formulas/chemistry/high-school/tx0svhbivo6aij0k6ssxtdj9bydta2zoff.png)
We are given:
![[OH^-]=4.5* 10^(-3)M](https://img.qammunity.org/2018/formulas/chemistry/high-school/5vy6ytsqmgqtubz9rpw60z9zs0s4769c3o.png)
Putting values in above equation, we get:


Hence, pOH of the given solution is 2.35