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19 votes
Find the Mean and Standard Deviation for the following situation.Hits in a Round of Hacky Sack137 66 1012313MeanStandard Deviaion

User Manuel Ferreria
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1 Answer

17 votes
17 votes

We have the scores: 13, 7, 6, 6, 10, 12, 3, 1, 3.

We have to calculate its mean and standard deviation.

We will start with the mean:


\begin{gathered} M=(1)/(n)\sum ^n_(i=1)\, x_i \\ M=(1)/(9)(13+7+6+6+10+12+3+1+3) \\ M=(61)/(9) \\ M=6.78 \end{gathered}

And the standard deviation can be calculated as:


\begin{gathered} s=\sqrt[]{(1)/(n-1)\sum ^n_(i=1)\, (x_i-M)^2} \\ \\ s=\sqrt[]{(1)/(8)((13-6.78)^2+(7-6.78)^2+(6-6.78)^2+(6-6.78)^2+(10-6.78)^2+(12-6.78)^2+(3-6.78)^2+(1-6.78)^2+(3-6.78)^2)} \\ \\ s=\sqrt[]{(139.56)/(8)} \\ \\ s=√(17.44)=4.18 \end{gathered}

The sample mean is 6.78 hits.

The sample standard deviation is 4.18 hits.

User LeMike
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