Question

The leg of a right triangle is 2 units and the hypotenuse is 4 units. What is the length, in units, of the other leg of the triangle?

A 2 units B. 6 units C.^12 units D.^20 units

Answer 1

Using the formula a^2 + b^2 = c^2
a=2; c=4
Therfore, c^2 - a^2 = b^ 2 is also true
4^2 - 2^2 = b^2
16 - 4 = b^2
12 = b^2
Since the square root of 12 is not a rational number the correct answer would be:
C) ^12 units
If I am interpreting the '^' before the 12 correctly as meaning the square root of.
Hope this helps!

Answer 2

Answer : The length of the other leg of the triangle is,
`√(12)units`

Step-by-step explanation :

Using Pythagoras theorem in ΔABC :

`(Hypotenuse)^2=(Perpendicular)^2+(Base)^2`

`(AC)^2=(AB)^2+(BC)^2`

Given:

Side AC = 4 units

Side AB = 2 units

Now put all the values in the above expression, we get the value of side BC.

`(4)^2=(2)^2+(BC)^2`

`BC=√((4)^2-(2)^2)`

`BC=√(12)units`

Thus, the length of the other leg of the triangle is,
`√(12)units`