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A car that originally cost $20,000 depreciates by 15% each year. In about how many years will the car be worth half its value? Use the equation 10,000 = 20,000(8.5)^x to solve the problem. Round your answer
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Apr 1, 2018
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A car that originally cost $20,000 depreciates by 15% each year. In about how many years will the car be worth half its value? Use the equation 10,000 = 20,000(8.5)^x to solve the problem. Round your answer to the nearest dollar.
Mathematics
high-school
BerggreenDK
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It's
0.5=0.85^x take natural log of both sides...
ln0.5/(ln0.85)=x
x≈4.265 years the car's value will be half of its original value...
y=20000(0.85)^(4.265)
y=$10000.00
Mavrck
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Apr 5, 2018
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Mavrck
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