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Quadratics 10x^2+ 23x =42Solve for x

User Wizard Of Kneup
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1 Answer

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First, bring the equation to the form ax²+bx+c=0 :

10x² + 23x - 42 = 0

Let's use quadratic formula: quadratic formula:

x =( -b ± √(b² - 4a*c) )/2a

a = 10

b=23

c=-42

x = (-23 ± √((-23)² - 4*10*-42)/2*10

x = (-23 ± √2209)/20

x1 = (-23 + √2209)/20 = (-23+47)/20 = 6/5 = 1.2

x2 = (-23 - √2209)/20 = (-23-47)/20 = -7/2 = -3.5

User John Vinyard
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