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What volume of a 6.67 m nacl solution contains 3.12 mol nacl??

User FoFox
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2 Answers

4 votes

If you are on ed. The answer is 0.468 L

User R Newbie
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6 votes

The volume of a 6.67 m nacl solution that contains 3.12 mol nacl is 0.468.

You just need to follow this formula:

C = n / V

So, it will be

V = n / C

= 3.12 / 6.67 moles / Liter

= 0.468 L

User Imbryk
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5.8k points