Question

Find the pressure of 5 L of a gas 27oC if number of moles is 0.8?

Answer 1

ANSWER

The pressure of the gas is 3.9 atm

Step-by-step explanation

Given information

The volume of the gas = 5L

The temperature of the gas = 27 degrees Celcius

The number of moles = 0.8 moles

To find the number of moles, we will need to apply the below formula

`PV\text{ = nRT}`

Where

P = pressure

V = volume

n = number of moles

R = gas constant

T = Temperature

Recall, that the gas constant is 0.082005 L atm mol^-1 K^-1

The next step is to convert the temperature from degrees Celcius to Kelvin

`\begin{gathered} T\degree\text{ K = t + 273.15} \\ T\degree K\text{ = 27 + 273.15} \\ T\degree K\text{ = 300.15} \end{gathered}`

The next step is to substitute the given data into the formula in order to find the pressure of the gas

`\begin{gathered} P\text{ }*\text{ 5 = 0.082005 }*\text{ 0.8 }*\text{ 300.15} \\ 5P\text{ = 19.6910} \\ \text{ Divide both sides by 5} \\ (5P)/(5)\text{ = }(19.6910)/(5) \\ P\text{ = 3.9 atm} \end{gathered}`

Hence, the pressure of the gas is 3.9 atm