Question

What volume of 14.7 M acetic acid (HC2H3O2) contains 9.7g of acetic acid?

Answer 1

First, we convert grams to moles using molar mass. Then we can use stoichiometry to convert moles to liters using the knowledge that M equals moles over liters.

So, to solve:

Step 1: 9.7 g acetic acid x (1 mole acetic acid/60.05g acetic acid) x (1 L/14.7 moles acetic acid) = 0.011 L acetic acid