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What is the triangle G at 294K for the following process at 1.0 atm?

What is the triangle G at 294K for the following process at 1.0 atm?-example-1
User Peri Hartman
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1 Answer

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15 votes

The ΔG is 3.66 kJ.

To calculate the ΔG of a chemical reaction, it is necessary to use the ΔG formula and replace the values. Remember to convert the J into kJ before the calculation:


\begin{gathered} \Delta G=\Delta H-T\cdot\Delta S \\ \Delta G=31.0(kJ)/(mol)-294K\cdot0.093\frac{kJ}{\text{mol}\cdot K} \\ \Delta G=3.66(kJ)/(mol) \end{gathered}

So, the ΔG of the reaction is 3.66 kJ.

User Brijesh Shiroya
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