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A plane, parallel to the base of a cone intersects the cone at the midpoint between points A and B. Determine the area of the cross-section formed by the intersection of the plane and the cone. Leave your answer in terms of pi.

User Smartmouse
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1 Answer

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Given that point of intersection is at half of the height, by similarity of triangles, the radius is half of

The the area is Pi*r^2 = Pi*(3in)^2 = Pi*9 in^2 = 9Piin^2


User Nogridbag
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