Question

Water has a specific heat of 4.186 J/g°C. How much heat is required to increase 10.0 g of water from 25.0°C to 30.0°C?

Answer 1

Mass times specific heat capacity times change in temperature = energy required to raise the temperature in this case

10x4.186x(30-25)=209.3 J

Answer 2

Answer: 209.3 J

Step-by-step explanation:

The heat required to increase the temperature of a substance is given by

`Q=mC_s \Delta T`

where

m is the mass of the substance

`C_s` is the specific heat capacity of the substance

`\Delta T` is the increase in temperature of the substance

In this problem, we have:

`m=10.0 g`

`C_s = 4.186 J/gC`

`\Delta T=30.0 C-25.0 C=5.0 C`

Substituting into the equation above, we find

`Q=(10.0 g)(4.186 J/gC)(5.0 C)=209.3 J`