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The table shows the daily high temperature (in Fahrenheit) for two cities for ten days. Which conclusion can be drawn from the data? The temperature range between the maximum and minimum values for city A is greater than the temperature range between the maximum and minimum values for city B. On average, city A was warmer than city B. The median is less for city A than for city B. The median and mode are different for city B. City A 90 85 84 85 80 82 83 85 89 82 City B 77 78 98 91 78 76 78 85 84 71

User Shrike
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2 Answers

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Answer: The answer is B. On average, city A was warmer than city B.

Explanation: I took the test and it was right

Hope ya'll have a good day

User Tartakynov
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4 votes

Answer:

B. On average, city A was warmer than city B.

Explanation:

Write the temperature for each city in ascending order:

City A

80 82 82 83 84 85 85 85 89 90

City B

71 76 77 78 78 78 84 85 91 98

City A:

The range = 90 - 80 = 10

Median = 84.5 (the mean between 84 and 85)

Mean
(80+ 82+ 82+ 83 +84 +85 +85+ 85 +89 +90)/(10)=84.5

Mode = 85

City B:

The range = 98 - 71 = 27

Median = 78 (the mean between 78 and 78)

Mean
(71 +76+ 77 +78+ 78 +78 +84+ 85 +91+ 98)/(10)=81.6

Mode = 78

Options:

A. The temperature range between the maximum and minimum values for city A is greater than the temperature range between the maximum and minimum values for city B. - False, because 10 is not greater than 27

B. On average, city A was warmer than city B. - True, because 84.5 > 81.6

C. The median is less for city A than for city B. - False because 84.5 is not less than 78

D. The median and mode are different for city B. - False, because the median and the mode are both 78.

User OrganicPanda
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