This is similar to exponential growth problems...
F=Ir^t F=final, I=initial, r=rate, t=time,
The main difference here is that the annual rate is compounded quarterly so
90000=I(1+.06/4)^(4t)
90000=I(1.015)^(4t) and since t=6 we have:
90000=I(1.015^24)
I=$62,958.95
verify...
F=62958.95(1.015^24)
F=$89999.996
F=$90000.00 rounded to nearest cent