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100 + 95 + 90 + 85 summation notation series solution

User Boban
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1 Answer

5 votes
Since we are decreasing by 5 each time, we can build up a series formula first.

S_n = (n)/(2)(2a + (n - 1)d)

S_n = (n)/(2)(200 - 5(n - 1))

Now, adding summation notation, we produce:


\sum_(k = 1)^(n)[(k)/(2)(200 - 5(k - 1))]
User Sandeep Thar
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