Question

This is for my Maths homework but I really don't know how to do the second one. Could someone please help.

Answer 1

The angle below 81° must be 180-81=99°

The sum of that angle, the 154°, and x must equal 360° so:

x=360-154-99

x=107°

...

That downward pointing triangle on the left side has equal sides with an apex angle of 24°. So its base angles must be (180-24)/2=78°. Then the angle opposite it in the base of the upward pointing triangle in the center is also 78°.

Now that means that base angles of the second downward pointing triangle on the right side must be equal to (180-78-44)=58°. And this downward triangle has equal length sides, so y° must be supplementary to 58°.

So y=180-58

y=122°

Answer 2

those tiny bars crossing those segments mean they are congruent
therefore you have isosceles triangles there
angles opposing congruent sides in isosceles triangles are also congruent
so
the other 2 angles in the 24 degrees triangle are (180-24)/2=78 degrees
now the angle close to the 24 from the 44 degrees triangle is also 78, that means that the third angle in the 44 triangle is 180-44-78=58
also the angle close to y is 58 (because of isosceles)
therefore y = 180-58=122 degrees