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What is the concentration of each of the individual ions in a 0.500M Ba(OH)2 solution.

User Lear
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Each mol Ba(OH)2 releases 2 mol OH-
Ba(OH)2 -----> Ba2+ + 2OH-

[Ba2+] = 0.500 M
[OH-] = 1.00 M

This assumes complete ionization (dissociation) of Ba(OH)2.
User Mtleis
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