Question

ABC is a right triangle. If AC=12 and BC=13, find AB.

Answer 1

Given: The

`\begin{gathered} AC=12 \\ BC=13 \end{gathered}`

To Determine:

`AB`

Using the Pythagoras theorem

`AB^2+AC^2=BC^2`
`\begin{gathered} AB^2=BC^2-AC^2 \\ AB^2=13^2-12^2 \\ AB^2=169-144 \\ AB^2=25 \\ AB=\sqrt[]{25} \\ AB=5 \end{gathered}`

Hence AB = 5