Question

Solve the system of equations algebraically

Answer 1

5x-2y=-4

5x=2y-4

x=(2y-4)/5 and this makes 2x-y=-1 become:

(4y-8)/5-y=-1

4y-8-5y=-5

-y-8=-5

-y=3

y=-3, making 2x-y=-1 become:

2x+3=-1

2x=-4

x=-2 so the solution is the point:

(-2, -3)

Answer 2

First, let's solve one of the equations for Y. The bottom one seems easier, so let's try that one:

2x-y=-1

Move the y over

2x=-1+y

Add 1

2x+1=y

Now let's substitute our y value into the other equation

5x-2(2x+1) = -4

Distribute

5x-4x-2 = -4

Combine like terms:

x-2 = -4

x= -2

Now let's solve for y with our x value

Y = 2(-2) + 1
Y = -4 +1

Y=-3

So your final answer is:
X= -2, Y= -3

Hope this Helps!