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Convert the polar representation of this complex number into its rectangular form: z=4(cos150°+ i sin150°) *the i before sin is an imaginary number*

User Mmarie
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2 Answers

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Use z=a+bi=|z|(cos (theta)+i sin(theta)) to find the complex number solutions. z0=z0= -2sqrt3 + 2i
User IlPittiz
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Answer:


z=2(-√(3)+i)

Explanation:

The given polar representation of the complex number is:


z=4(cos(150)^(\circ)+isin(150)^(\circ))

Thus, by solving the above equation, we have


z=4(cos(90+60)+isin(90+60))


z=4(-sin60^(\cic)+icos60^(\circ))


z=4((√(3))/(2)+i(1)/(2)


z=2(-√(3)+i)

which is the required rectangular form of the given polar complex number.

User Jonathan Irwin
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