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The coordinates of the vertices of △JKL are J(0, 2) , K(3, 1) , and L(1, −5) .

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The coordinates of the vertices of △JKL are J(0, 2) , K(3, 1) , and L(1, −5) . Drag-example-1
User Nathan Tew
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1 Answer

6 votes

we know that

If two lines are perpendicular, then the product of their slopes is equal to minus one

so


m1*m2=-1

we have


J(0,2)\\K(3,1)\\L(1,-5)

Remember that

the formula to calculate the slope between two points is equal to


m=((y2-y1))/((x2-x1))

Step 1

Find the slope JK

we have


J(0,2)\\K(3,1)

substitute in the slope's formula


m=((1-2))/((3-0))


m=((-1))/((3))


mJK=-(1)/(3)

Step 2

Find the slope KL

we have


K(3,1)\\L(1,-5)

substitute in the slope's formula


m=((-5-1))/((1-3))


m=((-6))/((-2))


mKL=3

Step 3

Find the slope JL

we have


J(0,2)\\L(1,-5)

substitute in the slope's formula


m=((-5-2))/((1-0))


m=((-7))/((1))


mJL=-7/tex]</p><p><strong>Step 4</strong></p><p><u>Verify if the sides of the triangle are perpendicular</u></p><p>Multiply the slopes</p><p><strong>JK and KL</strong></p><p>[tex]mJK=-(1)/(3)


mKL=3


-(1)/(3)*3=-1 ------> sides JK and KL are perpendicular

when verifying that it has two perpendicular sides, it is not necessary to continue verifying the others, since a triangle can only have a single right angle

therefore

the answer in the attached figure



The coordinates of the vertices of △JKL are J(0, 2) , K(3, 1) , and L(1, −5) . Drag-example-1
User Es
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8.6k points