B. Recall that the general equation of a line is of the form y=mx+b where b is the value of y at which the graph crosses the y axis and m is the slope of the line. Based on the graph, we can tell that the lines crosses the y-axis at the value y=0. So b=0. We must determine m. We are told that the length and height are in the ration 11 to 4, this means that whenever we increment the value of X by 11, the value of Y increments by 4. So, having our equation, whenever we replace x = 11, we must have y =4. then, we have the equation
4 = 11m. Dividing both sides by 11 we get m = 4/11. So the equation we were looking for is y = 4/11 x. From this equation, we can multiply by 11 and then divide by 4 on both sides, so we get 11/4 y = x.
C. Consider an approximation of the graph as follows:
You can pick any point that is on the line. Take for example the one I've drawn. By having m = 4/11 it means that whenever we draw a horizontal line that is parallel to the x-axis that start at the point we chose, and whose lenght is 11 (red line in the drawing), if we then draw a vertical line (blue line)that is parallel to the y-axis, as soon as this vertical line touches the original line, we will form a triangle whose height necessarily has length equal to 4.