Question

Write an equation and solve. One telephone company charges $16.95 per month and $0.05 per minute for local calls. Another company charges $22.95 per month and $0.02 per minute for local calls. For what number of minutes of local calls per month is the cost of the plans the same?

A. 16.95 + 0.05m = 22.95 + 0.02m; 200 min

B. 16.95 + 0.05m + 22.95 + 0.02m = 0; 570 min

C. 16.95 + 0.05m = 22.95 + 0.02m; 2 min

Answer 1

16.95+.05x=22.95+.02x

Subtract .02x from each side and subtract 16.95 from each side

.03x=6
Divide by .03

x=200 minutes.

Your answer is A

Answer 2

The correct option is A. 16.95 + 0.05m = 22.95 + 0.02m; 200 min

Explanation:

Consider the provided information.

One telephone company charges $16.95 per month and $0.05 per minute for local calls.

Let m is represents the number of minutes.

Therefore, the cost of plane can be represent as:

`16.95+0.05m`

Another company charges $22.95 per month and $0.02 per minute for local calls.

Therefore, the cost of plane can be represent as:

`22.95+0.02m`

Now equate both the equations:

`16.95+0.05m=22.95+0.02m`

`16.95+0.03m=22.95`

`0.03m=22.95-16.95`

`0.03m=6`

`m=200`

For 200 minutes the cost of both plans remains the same.

Hence, the correct option is A. 16.95 + 0.05m = 22.95 + 0.02m; 200 min