Question

4x + 4y=48 3x = 2y + 6

Answer 1

Equation

`\begin{gathered} 4x+4y=48 \\ 3x=2y+6 \end{gathered}`

Procedure

By subtracting the value of x for the second equation and replacing in the first equation

`4((2y+6)/(3))+4y=48`
`\begin{gathered} (8y)/(3)+8+4y=48 \\ (20y)/(3)=48-8 \\ 20y=3(40) \\ y=(120)/(20) \\ y=6 \end{gathered}`

Now, for x

`\begin{gathered} x=(2y+6)/(3) \\ x=(2\cdot6+6)/(3) \\ x=(12+6)/(3) \\ x=(18)/(3) \\ x=6 \end{gathered}`

The solutions to system equations are:

x= 6 and y= 6