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What is the [OH–] in a solution with a pOH of 4.22?
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What is the [OH–] in a solution with a pOH of 4.22?

User Lyuben Todorov
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We are asked what is the [OH-] in a solution with a POH of 4.22 and to solve this we need to use the equation written below:
POH= -log [OH-]
10^-poh=[OH-]
10^-4.22=[OH-]
6.03X10^-5 M = [OH-]

The answer is 6.03x10^-5 M.
User Rfgamaral
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