Answer:
The correct answer is - A, B, C, and D.
Step-by-step explanation:
Colorblindness is a sex-linked recessive genetic disease. It is present in females only if both X chromosomes are homozygous recessive if only one copy of the recessive gene present female will be considered as a carrier and normal. In males, even one copy of the diseased gene can cause color blindness as they carry one X chromosome.
So kids of Lupa XHXh and Clifford XhY will be formed by gametes XH, Xh and Xh, Y of respective parents. By the cross of these offspring will be XHXh (carrier normal female), XHY( normal male), XhXh ( disease female) and XhY (color blind male).
Thus, the correct answer is option -A, B, C, and D.