Question

What is the percentage increase IN kinetic energy(K.E) ,If the momentum(p) of a moving body is increase by 10%?And How? (If K.E= p^2/2m)

Answer 1

`KE = (p^2)/(2m)` (start kinetic energy)

`KE = ((1.1p)^2)/(2m) =1.21 * (p^2)/(2m)`

`KE_n_e_w=1.21* KE_o_l_d`
Therefore increasing the momentum by 10% increases KE by 21%.