Question

Write a balanced equation for the reaction between hydroiodic acid and lithium hydrosulfite.

Answer 1

HI + LiHSO3 → H2O + SO2 + LiI

Step-by-step explanation:

Step 1: Data given

hydroiodic acid = HI

lithium hydrosulfite = LiHSO3

Step 2: The unbalanced equation

HI + LiHSO3 → H2O + SO2 + LiI

Step 3: the balanced equation

On the left side we have 2x H (1x in HI and 1x in LiHSO3). On the right side we have 2 moles H (in H2O). The amount of H is balanced.

The amount of moles I , on the left is 1, The amount of moles I on the right is 1 mol. This amount is balanced.

On the left side we have 3x O. (3x in LiHSO3). On the right side we have 3x O, (1x in H2O and 2x in SO2). The amount of O is balanced.

HI + LiHSO3 → H2O + SO2 + LiI

Answer 2

Balanced equations for a reaction shows the number of elements within the equation. The coefficient reflects all of the elements that it is in front of and subscript number reflects the one element it is in front of . They both are important when determining the number of elements in a balanced equation. If you have 3H2, then you have to multiply and there will be 6 hydrogen elements. The balanced equation for the reaction between hydroiodic acid and lithium hydrosulfite:
HI +LiHSO3 -----> H2O +SO2+LiI