Question

The graph of y=11x^2+c is a parabola with a vertex at the origin ?

Answer 1

This question is worded oddly.

y = 11
`x^(2)` is a parabola with a vertex at the origin. (0,0)

Depending on what 'c' is, that will shift the parabola positive or negative. Therefore in general terms, the vertex will be at the location of 'c'.