Answer: ((x^2 + 3)^9)/9 +c
Explanation:
Let, x² + 3 = u
⇒2x dx = du
Now, substituting, we get,
∫u^8 du
= (u^(8+1))/(8+1)
= (u^9)/9
= ((x^2 + 3)^9)/9 +c
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