Question

Water

SA = 2tr2 + 2nrh
(Use 3.14 for 1.)
Find the surface area
of a water tower that is
40 feet tall and 20 feet
across the base.
square feet
Do NOT round your answer.

Answer 1

the surface area is 3140 square feet

Explanation:

The computation of the surface area is given below:

Given that

Diameter = 20 feet

radius = 20 ÷ 2 = 10 feet

Surface area =
`2\pi r^2 + 2\pi rh`

= 2 × 3.14 × (10)^2 + 2 × 3.14 × 10 × 40

= 6.28 × 100 + 6.28 × 400

= 628 + 25.12 × 100

= 628+ 2512

= 3140 square feet

hence, the surface area is 3140 square feet