Question

I need help with these twooo​

Answer 1

Question 5

We get n=42.15 and o=71.5

Question 6

We get e=15.32 and t=17.88

Explanation:

Question 5

The triangles are similar.

So, the ratio of corresponding sides will be similar.

`(53)/(n)=(88)/(70)=(90)/(o)`

First we will solve
`(53)/(n)=(88)/(70)` to find value of n.

Cross multiply

`53*70=88*n\\n=(3710)/(88)\\n=42.15\\`

Now, we will solve
`(88)/(70)=(90)/(o)` to find value of o

`88*o = 90*70\\o=(6300)/(88)\\o=71.5\\`

So, We get n=42.15 and o=71.5

Question 6

The triangles are similar.

So, the ratio of corresponding sides will be similar.

`(9.6)/(e)=(5.7)/(9.1)=(11.2)/(t)`

First we will solve
`(9.6)/(e)=(5.7)/(9.1)` to find value of n.

Cross multiply

`9.1*9.6=e*5.7\\e=(87.36)/(5.7)\\e=15.32\\`

Now, we will solve
`(5.7)/(9.1)=(11.2)/(t)` to find value of o

`5.7*t = 11.2*9.1\\t=(101.92)/(5.7)\\t=17.88\\`

So, We get e=15.32 and t=17.88