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How many different committees can be formed from 8 teachers and 48 students if the committee consists of 3 teachers and 4 ​students?

User Matt Baker
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2 Answers

4 votes
Since we don't care about the order in which we select people, we will use the combinatoric approach, rather than permutations.
Since we want to select 3 teachers from a total of 8, this is the notation to select 3 teachers from 8 (objects).

Teachers :
^(8)C_3
Similarly, students :
^(48)C_(4)

Now, since we want both at the same time, we will need to multiply both to yield your final answer:
^(8)C_3 \cdot ^(48)C_(4) = 10,896,480 different ways.
User Foroogh Varmazyar
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6.3k points
2 votes
As many as you'd like
User Zachary Sweigart
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