x+2y=8
2y=-x+8
y=-x/2+4
So for L to be perpendicular to this its slope must be the negative reciprocal of y's slope...
-1m/2=-1, m=2
So L has a slope of 2
L=2x+b, since it passes through the origin its y-intercept is zero so
L=2x or back in y terms
y=2x, by convention you want to arrange this so x has a positive coefficient...
2x-y=0
So B, is the correct answer.