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How would you multiply (3x-8)(2x^2+4x-9)
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How would you multiply (3x-8)(2x^2+4x-9)

User Utapyngo
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1 Answer

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(3x-8)(2x^2+4x-9)= 6x^3−4x^2−59x+72
Hope I helped! ( Smiles )
User Sheina
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