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Find the surface S of the balloon as a function of the time t.

Find the surface S of the balloon as a function of the time t.-example-1
User Bigerock
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seems to be just a matter of S( r(t) )


\bf \textit{surface area of a sphere}\\\\ S=4\pi r^2\qquad \begin{cases} r=radius\\ --------\\ \boxed{r(t)}=(3)/(8)t^4 \end{cases}\implies S(t)=4\pi \left( \boxed{(3)/(8)t^4} \right)^2
User Mike Eng
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