Question

If a polynomial function f(x) has roots 3 and \sqrt(7), what must also be a root of f(x)?

Answer 1

When one of the roots of a polynomial function is an irrational number that cannot be expressed in any other way possible, it is known that its conjugate must also be a root of the function. If 3(sqrt of 7) is a root then, -3(sqrt of 7) is also a root. 

Answer 2

The other root should be negative square root of 7

Explanation:

If a polynomial function f(x) has roots 3 and \sqrt(7), what must also be a root of f(x)?

When we have a root of square root function, we have both the positive and the negative values.

This is because when we take a square root of a number, we get two solutions a positive and a negative.

This is why the other root will be negative square root of 7.