Question

the axis of symmetry for the hraph of the function f (x) = 3x^2 + bx + 4 is x=3/2. what is the value of b

Answer 1

in form f(x)=ax^2+bx+c

the axis of symmetry is -b/2a so


3/2=-b/2a

given
f(x)=3x^2+bx+4
a=3
b=b

-b/(2*3)=3/2
-b/6=3/2
-b=18/2
-b=9
b=-9