Question

F(x)=(x+2)^2+6Equation of axis of symmetry of parabola.

Answer 1

For this case we have the following function:

`y=(x+2)^2+6`

We can expand the terms and we have:

y= x^2 +4x+4 +6 = x^2 +4x+10

And then we can find the equation for the axis of symettry with:

`y=-(b)/(2a)`

a= 1, b= 4 then

`y=-(4)/(2\cdot1)=-2`

Then the answer for this case is:

y= -2