Answer:
-11
Explanation:
The given system of equations solved by matrix method is to arrange all coefficients into a matrix, and then making zeros in specific columns and rows, until we get an equation with just one variable.


In matrix arrangement:
![\left[\begin{array}{ccc}(1)/(2) &1&3\\3&4&1\end{array}\right] \\](https://img.qammunity.org/2018/formulas/mathematics/high-school/uir2o5rpgsy85at9wx68hi5kgcnlma04w2.png)
Multiplying by 4 the first row and then subtracting with the second row, we have:
![\left[\begin{array}{ccc}-1 &0&11\\3&4&1\end{array}\right]](https://img.qammunity.org/2018/formulas/mathematics/high-school/8s5oz5pde1ooj9apoasapagzu9ddeamt8e.png)
From the firs row, we find that:

Therefore, the right answer is -11.