Question

How many moles of calcium nitrate would react with 4.55 moles of chromium(iii) sulfate to produce calcium sulfate and chromium(iii) nitrate

Answer 1

The answer is 13.65 moles of Ca(NO3)2

Step-by-step explanation:

the balanced equation is as follows:

3Ca(NO3)2 + Cr2(SO4)3 = 3CaSO4 + 2Cr(NO3)2

According to the balanced equation, 3 moles of Ca(NO3)2 react with 1 mole of Cr2(SO4)3. Using a simple rule of three, we can calculate the number of moles of Ca(NO3)2 that would react with 4 moles of Cr2(SO4)3. As follows:

3 moles Ca(NO3)2------------------- 1 mol Cr2(SO4)3

X moles Ca(NO3)2------------------- 4.55 moles Cr2(SO4)3

Clearing X:

X moles Ca(NO3)2 = 3*4.55 = 13.65 moles

Answer 2

The equation for the reaction between the calcium nitrate and chromium sulfate to form calcium sulfate and chromium(iii) nitrate is,
3Ca(NO3)2 + Cr2(SO4)3 --> 3CaSO4 + 2Cr(NO3)3
The balanced equation shows that for every 1 mole of chromium sulfate, there will be 3 moles of calcium nitrate. Therefore for this item, there will be 4.55 moles times 3 which is equal to 13.65.