Question

Please help me solve this problem as a fraction in simplest form :(

Answer 1

3/16

Step-by-step explanation:

• The total number of sections in the spinner, n(S)=8

,

• The number of gray sections in the spinner, n(G)= 6

,

• The number of blue sections in the spinner, n(B)= 2

The probability that the first spinner lands on gray(G) and the second lands on blue(B):

`\begin{gathered} P(GB)=P(G)* P(B) \\ =(n(G))/(n(S))*(n(B))/(n(S)) \\ =(6)/(8)*(2)/(8) \\ =(12)/(64) \\ =(3)/(16) \end{gathered}`

The required probability is 3/16.