Question

An object has a charge value of 3x10^-6C. What is the value of the electric field for thisone charge, 0.005m away from the charge? (k = 9x10 ) (Hint: We are looking for theelectric field "E" here, not the force.) **Make sure to pay attention that the charge hasa negative exponent.

Answer 1

Answer: the value of the electric field is 10.8 x 10^8 N/C

Step-by-step explanation:

We would apply the formula for calculating electric field which is expressed as

E = kQ/r^2

Where

E is the magnitude of the electric field

k is the coulomb constant and its value is 9 x 10^9 Nm^2/C^2

Q1 is the magnitude of the charge

r is the distance away from the charge

From the information given,

Q = 3 x 10^-6C

r = = 0.005

By substituting these values into the formula,

E = (9 x 10^9 x 3 x 10^-6)/(0.005)^2

E = 10.8 x 10^8 N/C