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The sum of the squares of two consecutive integers is 41. find the integers
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The sum of the squares of two consecutive integers is 41. find the integers
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May 15, 2018
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The sum of the squares of two consecutive integers is 41. find the integers
Mathematics
high-school
Birderic
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Birderic
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≡ We know that:
⇔ Consider the first integer is
⇔ So, the next integer is
≡ Solution:
⇒
⇒
⇒
⇒
⇒
║
∴ So, there are 2 options,
or
Alexey Soshin
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May 17, 2018
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Alexey Soshin
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Start by declaring variables.
Since we have two consecutive integers, let your variables be x and x + 1.
Thus, we can say that:
x² + (x + 1)² = 41
x² + x² + 2x + 1 = 41
2x² + 2x - 40 = 0
x² + x - 20 = 0
(x + 5)(x - 4) = 0
So, x = -5 or 4.
Thus, we can have -5 and -4,
or 4 and 5.
Xirururu
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May 19, 2018
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Xirururu
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