1 Answer

Itdxer · Answer 1 · 2023-03-21T02:10:29+0000

Given a cylinder of radius = r = 6 ft, and a height = h = 10 ft

A conic portion removed from the cylinder

So, the volume of the remaining portion =

the volume of the cylinder - the volume of the cone

The volume of the cylinder =

$\pi\cdot r^2\cdot h$

The volume of the cone =

$(1)/(3)\pi\cdot r^2\cdot h$

so, the answer will be =

$\pi\cdot r^2\cdot h-(1)/(3)\pi\cdot r^2\cdot h=(2)/(3)\cdot\pi\cdot r^2\cdot h=(2)/(3)\pi\cdot6^2\cdot10=240\pi$

So, the answer is option 3) 240pi

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