Question

A 10-cm-diameter parallel-plate capacitor has a 1.0 mm spacing. the electric field between the plates is increasing at the rate 5.0×105 v/ms .

Answer 1

The electric field between the plates of the parallel-plate capacitor is 5.0 × 10^8 V/m.

Step-by-step explanation:

The electric field between the plates of a parallel-plate capacitor can be calculated using the formula E = V / d, where E is the electric field, V is the potential difference, and d is the spacing between the plates. In this case, the diameter of the capacitor is 10 cm, so the radius is 5 cm or 0.05 m. The spacing is given as 1.0 mm, which is equivalent to 0.001 m. Therefore, the electric field can be calculated as follows:

E = V / d = (5.0 × 10^5 V/ms) / (0.001 m) = 5.0 × 10^8 V/m.

The electric field is 5.0 × 10^8 V/m.

Answer 2

After thorough researching, if a 10-cm-diameter parallel-plate capacitor has 1.0 mm spacing and the electric field between the plates is increasing at the rate 5.0×105 v/ms, the magnetic field strength from the distances should be 8.2 cm. The correct answer to the following statement is 8.2 cm.