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Heart Rates For a certain group of individuals, the average heart rate is 74 beats per minute. Assume the variable is normally distributed and the standarddeviation is 2 beats per minute. If a subject is selected at random, find the probability that the person has the following heart rate. Use a graphing calculator.Round the answers to four decimal places.Between 71 and 75 beats per minute.P (71

User Diego Melo
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Let X be the number of heartbeats of any individual in the group.

The variable X is normally distributed with mean 74 beats per minute,


\mu=74

The standard deviation is 2 beats per minute,


\sigma=2

Consider the formula of z-score corresponding to any value of X=x as,


z=(x-\mu)/(\sigma)

It is required to find the probability that the number of heartbeats of a randomly selected person lies between 71 and 75.

This can be obtained as follows,


\begin{gathered} P(71From the Standard Normal Distribution Table,[tex]\begin{gathered} \phi(0.5)=0.1915 \\ \phi(1.5)=0.4332 \end{gathered}

Substitute the values and simplify,


\begin{gathered} =0.4332+0.1915 \\ =0.6247 \end{gathered}

User MRu
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