Question

In a circle, a 90°sector area 36 what is the radius of the circle

Answer 1

`\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\pi \theta r^2}{360}\qquad \begin{cases} \theta=\textit{angle in degrees}\\ r=radius\\ ----------\\ \theta=90\\ A=36 \end{cases}\implies 36=\cfrac{90\cdot \pi \cdot r^2}{360}`

solve for "r"