Question

For her phone service, Carmen pays a monthly fee of $24, and she pays an additional $0.06 per minute of use. The least she has been charged$88.02 What are the possible numbers of minutes she has used her phone in a month?Use m for the number of minutes, and solve your inequality for m.

Answer 1

m ≥ 1067

Step-by-step explanation:

Monthly fee = $24

Additional fee = $0.06 per minute

let the number of minutes = m

Amount charge is atleast $88.02

Atleast is the same as ≥ $88.02

`\text{Monthly fe}e\text{ + additional fe}e\text{ (number of minute) }\ge$88.02$`
`\begin{gathered} 24\text{ + 0.06 (m) }\ge\text{ }88.02 \\ 24\text{ + 0.06m }\ge\text{ }88.02 \\ \text{subtract 24 from both sides:} \\ 0.06m\text{ }\ge\text{ }88.02\text{ - 24} \end{gathered}`
`\begin{gathered} 0.06m\text{ }\ge\text{64.02} \\ \text{divide both sides by 0.06:} \\ (0.06m)/(0.06)\text{ }\ge\text{ }\frac{\text{64.02}}{0.06} \end{gathered}`
`m\text{ }\ge\text{ 1067}`

She has used her phone for less than 1067 minutes

m ≥ 1067